Integrand size = 20, antiderivative size = 198 \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 \left (b^2-4 a c\right ) x^6}+\frac {b \left (15 b^2-52 a c\right ) \sqrt {a+b x^3+c x^6}}{12 a^3 \left (b^2-4 a c\right ) x^3}-\frac {\left (5 b^2-4 a c\right ) \text {arctanh}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{8 a^{7/2}} \]
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Time = 0.14 (sec) , antiderivative size = 198, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 6, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {1371, 754, 848, 820, 738, 212} \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=-\frac {\left (5 b^2-4 a c\right ) \text {arctanh}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{8 a^{7/2}}+\frac {b \left (15 b^2-52 a c\right ) \sqrt {a+b x^3+c x^6}}{12 a^3 x^3 \left (b^2-4 a c\right )}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 x^6 \left (b^2-4 a c\right )}+\frac {2 \left (-2 a c+b^2+b c x^3\right )}{3 a x^6 \left (b^2-4 a c\right ) \sqrt {a+b x^3+c x^6}} \]
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Rule 212
Rule 738
Rule 754
Rule 820
Rule 848
Rule 1371
Rubi steps \begin{align*} \text {integral}& = \frac {1}{3} \text {Subst}\left (\int \frac {1}{x^3 \left (a+b x+c x^2\right )^{3/2}} \, dx,x,x^3\right ) \\ & = \frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {2 \text {Subst}\left (\int \frac {\frac {1}{2} \left (-5 b^2+12 a c\right )-2 b c x}{x^3 \sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{3 a \left (b^2-4 a c\right )} \\ & = \frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 \left (b^2-4 a c\right ) x^6}+\frac {\text {Subst}\left (\int \frac {-\frac {1}{4} b \left (15 b^2-52 a c\right )-\frac {1}{2} c \left (5 b^2-12 a c\right ) x}{x^2 \sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{3 a^2 \left (b^2-4 a c\right )} \\ & = \frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 \left (b^2-4 a c\right ) x^6}+\frac {b \left (15 b^2-52 a c\right ) \sqrt {a+b x^3+c x^6}}{12 a^3 \left (b^2-4 a c\right ) x^3}+\frac {\left (5 b^2-4 a c\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x+c x^2}} \, dx,x,x^3\right )}{8 a^3} \\ & = \frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 \left (b^2-4 a c\right ) x^6}+\frac {b \left (15 b^2-52 a c\right ) \sqrt {a+b x^3+c x^6}}{12 a^3 \left (b^2-4 a c\right ) x^3}-\frac {\left (5 b^2-4 a c\right ) \text {Subst}\left (\int \frac {1}{4 a-x^2} \, dx,x,\frac {2 a+b x^3}{\sqrt {a+b x^3+c x^6}}\right )}{4 a^3} \\ & = \frac {2 \left (b^2-2 a c+b c x^3\right )}{3 a \left (b^2-4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}-\frac {\left (5 b^2-12 a c\right ) \sqrt {a+b x^3+c x^6}}{6 a^2 \left (b^2-4 a c\right ) x^6}+\frac {b \left (15 b^2-52 a c\right ) \sqrt {a+b x^3+c x^6}}{12 a^3 \left (b^2-4 a c\right ) x^3}-\frac {\left (5 b^2-4 a c\right ) \tanh ^{-1}\left (\frac {2 a+b x^3}{2 \sqrt {a} \sqrt {a+b x^3+c x^6}}\right )}{8 a^{7/2}} \\ \end{align*}
Time = 0.66 (sec) , antiderivative size = 166, normalized size of antiderivative = 0.84 \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\frac {-8 a^3 c-15 b^3 x^6 \left (b+c x^3\right )+2 a^2 \left (b^2+10 b c x^3-12 c^2 x^6\right )+a b x^3 \left (-5 b^2+62 b c x^3+52 c^2 x^6\right )}{12 a^3 \left (-b^2+4 a c\right ) x^6 \sqrt {a+b x^3+c x^6}}+\frac {\left (5 b^2-4 a c\right ) \text {arctanh}\left (\frac {\sqrt {c} x^3-\sqrt {a+b x^3+c x^6}}{\sqrt {a}}\right )}{4 a^{7/2}} \]
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\[\int \frac {1}{x^{7} \left (c \,x^{6}+b \,x^{3}+a \right )^{\frac {3}{2}}}d x\]
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none
Time = 0.35 (sec) , antiderivative size = 615, normalized size of antiderivative = 3.11 \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\left [-\frac {3 \, {\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{12} + {\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{9} + {\left (5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} x^{6}\right )} \sqrt {a} \log \left (-\frac {{\left (b^{2} + 4 \, a c\right )} x^{6} + 8 \, a b x^{3} + 4 \, \sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {a} + 8 \, a^{2}}{x^{6}}\right ) - 4 \, {\left ({\left (15 \, a b^{3} c - 52 \, a^{2} b c^{2}\right )} x^{9} + {\left (15 \, a b^{4} - 62 \, a^{2} b^{2} c + 24 \, a^{3} c^{2}\right )} x^{6} - 2 \, a^{3} b^{2} + 8 \, a^{4} c + 5 \, {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{3}\right )} \sqrt {c x^{6} + b x^{3} + a}}{48 \, {\left ({\left (a^{4} b^{2} c - 4 \, a^{5} c^{2}\right )} x^{12} + {\left (a^{4} b^{3} - 4 \, a^{5} b c\right )} x^{9} + {\left (a^{5} b^{2} - 4 \, a^{6} c\right )} x^{6}\right )}}, \frac {3 \, {\left ({\left (5 \, b^{4} c - 24 \, a b^{2} c^{2} + 16 \, a^{2} c^{3}\right )} x^{12} + {\left (5 \, b^{5} - 24 \, a b^{3} c + 16 \, a^{2} b c^{2}\right )} x^{9} + {\left (5 \, a b^{4} - 24 \, a^{2} b^{2} c + 16 \, a^{3} c^{2}\right )} x^{6}\right )} \sqrt {-a} \arctan \left (\frac {\sqrt {c x^{6} + b x^{3} + a} {\left (b x^{3} + 2 \, a\right )} \sqrt {-a}}{2 \, {\left (a c x^{6} + a b x^{3} + a^{2}\right )}}\right ) + 2 \, {\left ({\left (15 \, a b^{3} c - 52 \, a^{2} b c^{2}\right )} x^{9} + {\left (15 \, a b^{4} - 62 \, a^{2} b^{2} c + 24 \, a^{3} c^{2}\right )} x^{6} - 2 \, a^{3} b^{2} + 8 \, a^{4} c + 5 \, {\left (a^{2} b^{3} - 4 \, a^{3} b c\right )} x^{3}\right )} \sqrt {c x^{6} + b x^{3} + a}}{24 \, {\left ({\left (a^{4} b^{2} c - 4 \, a^{5} c^{2}\right )} x^{12} + {\left (a^{4} b^{3} - 4 \, a^{5} b c\right )} x^{9} + {\left (a^{5} b^{2} - 4 \, a^{6} c\right )} x^{6}\right )}}\right ] \]
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\[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int \frac {1}{x^{7} \left (a + b x^{3} + c x^{6}\right )^{\frac {3}{2}}}\, dx \]
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Exception generated. \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\text {Exception raised: ValueError} \]
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\[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int { \frac {1}{{\left (c x^{6} + b x^{3} + a\right )}^{\frac {3}{2}} x^{7}} \,d x } \]
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Timed out. \[ \int \frac {1}{x^7 \left (a+b x^3+c x^6\right )^{3/2}} \, dx=\int \frac {1}{x^7\,{\left (c\,x^6+b\,x^3+a\right )}^{3/2}} \,d x \]
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